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Multiple choice
Per this lesson's geometric picture of Grover, where the initial state is at angle
θ
\theta
θ
with
sin
(
θ
)
=
1
/
N
\sin(\theta) = 1/\sqrt{N}
sin
(
θ
)
=
1/
N
, what does a single Grover iteration do to the state vector?
🔬 try it before you answer
Rotates it by a full
π
\pi
π
, returning it to the start
Reflects it about the marked state, leaving the angle unchanged
Rotates it by
θ
\theta
θ
away from the marked state
Rotates it by
2
θ
2\theta
2
θ
toward the marked state
∣
ω
⟩
|\omega\rangle
∣
ω
⟩
Check answer