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An entanglement witness gives
W
=
1
/
2
−
∣
⟨
Φ
+
∣
ψ
⟩
∣
2
W = 1/2 - |\langle\Phi^+|\psi\rangle|^2
W
=
1/2
−
∣
⟨
Φ
+
∣
ψ
⟩
∣
2
for the target Bell state
∣
Φ
+
⟩
|\Phi^+\rangle
∣
Φ
+
⟩
. The test state is exactly
∣
ψ
⟩
=
∣
Φ
+
⟩
|\psi\rangle = |\Phi^+\rangle
∣
ψ
⟩
=
∣
Φ
+
⟩
, so the overlap
∣
⟨
Φ
+
∣
ψ
⟩
∣
2
=
1
|\langle\Phi^+|\psi\rangle|^2 = 1
∣
⟨
Φ
+
∣
ψ
⟩
∣
2
=
1
. What is the witness value
W
W
W
?
🔬 try it before you answer
−
1
/
2
=
−
0.5
-1/2 = -0.5
−
1/2
=
−
0.5
+
1
/
2
=
0.5
+1/2 = 0.5
+
1/2
=
0.5
0
0
0
+
1
+1
+
1
Check answer