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Multiple choice
The linear variational method diagonalizes
[
a
b
b
d
]
\begin{bmatrix}a & b \\ b & d\end{bmatrix}
[
a
b
b
d
]
with
a
=
1
a = 1
a
=
1
,
b
=
1
b = 1
b
=
1
,
d
=
3
d = 3
d
=
3
. The lower eigenvalue is
mean
−
(
(
a
−
d
)
/
2
)
2
+
b
2
\text{mean} - \sqrt{((a-d)/2)^2 + b^2}
mean
−
((
a
−
d
)
/2
)
2
+
b
2
. What is it?
0.5858
2.0
3.4142
1.0
Check answer