Multiple choice
Execute the circuit and measure. How likely is the outcome |01⟩?
// |00> --x(1)--> |01> --h(0)--> (|01>+|11>)/sqrt2 --cx(0,1)--> (|01>+|10>)/sqrt2 // --z(0)--> (|01>-|10>)/sqrt2, the singlet. const c = circuit(2); c.x(1); c.h(0); c.cx(0, 1); c.z(0); return c;
Commit your prediction for P(|01⟩) — then run it.