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Multiple choice
An electron in hydrogen falls from
n
=
3
n=3
n
=
3
to
n
=
2
n=2
n
=
2
, where
E
n
=
−
13.6
E_n = -13.6
E
n
=
−
13.6
eV
/
n
2
/ n^2
/
n
2
. The emitted photon's energy equals
E
3
−
E
2
E_3 - E_2
E
3
−
E
2
(the energy lost). What is that photon energy in eV?
1.51 (=
∣
E
3
∣
|E_3|
∣
E
3
∣
)
1.89
3.40 (=
∣
E
2
∣
|E_2|
∣
E
2
∣
)
-1.89 (sign flipped:
E
2
−
E
3
E_2 - E_3
E
2
−
E
3
)
Check answer