Multiple choice
Execute the circuit and measure. How likely is the outcome |01⟩?
const c = circuit(2); c.h(0); // (|00⟩ + |10⟩)/√2 c.x(1); // (|01⟩ + |11⟩)/√2 c.cx(0, 1); // |11⟩ → |10⟩ ⇒ (|01⟩ + |10⟩)/√2 return c;
Commit your prediction for P(|01⟩) — then run it.