Multiple choice
Execute the circuit and measure. How likely is the outcome |0⟩?
const c = circuit(1); c.rx(Math.PI / 2, 0); // pi/2 pulse: tip into the equatorial plane c.rz(Math.PI / 2, 0); // Larmor precession about z by pi/2 return c;
Commit your prediction for P(|0⟩) — then run it.