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Multiple choice
For an orbital angular momentum state with quantum number
l
=
2
l = 2
l
=
2
, the operator
L
2
L^2
L
2
has eigenvalue
l
(
l
+
1
)
l(l+1)
l
(
l
+
1
)
(in units where
ℏ
=
1
\hbar = 1
ℏ
=
1
). What is that eigenvalue?
4
(
=
l
2
)
4 (= l^2)
4
(
=
l
2
)
6
5
(
=
2
l
+
1
)
5 (= 2l+1)
5
(
=
2
l
+
1
)
9
(
=
(
l
+
1
)
2
)
9 (= (l+1)^2)
9
(
=
(
l
+
1
)
2
)
Check answer