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Multiple choice
The final Hadamard in Deutsch's algorithm maps the register qubit to a computational basis state. What are
H
∣
+
⟩
H|+\rangle
H
∣
+
⟩
and
H
∣
−
⟩
H|-\rangle
H
∣
−
⟩
?
H
∣
+
⟩
=
∣
0
⟩
H|+\rangle = |0\rangle
H
∣
+
⟩
=
∣0
⟩
and
H
∣
−
⟩
=
∣
0
⟩
H|-\rangle = |0\rangle
H
∣
−
⟩
=
∣0
⟩
H
∣
+
⟩
=
∣
+
⟩
H|+\rangle = |+\rangle
H
∣
+
⟩
=
∣
+
⟩
and
H
∣
−
⟩
=
∣
−
⟩
H|-\rangle = |-\rangle
H
∣
−
⟩
=
∣
−
⟩
H
∣
+
⟩
=
∣
1
⟩
H|+\rangle = |1\rangle
H
∣
+
⟩
=
∣1
⟩
and
H
∣
−
⟩
=
∣
0
⟩
H|-\rangle = |0\rangle
H
∣
−
⟩
=
∣0
⟩
H
∣
+
⟩
=
∣
0
⟩
H|+\rangle = |0\rangle
H
∣
+
⟩
=
∣0
⟩
and
H
∣
−
⟩
=
∣
1
⟩
H|-\rangle = |1\rangle
H
∣
−
⟩
=
∣1
⟩
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