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Multiple choice
The Balmer series of hydrogen follows
1
/
λ
=
R
H
(
1
/
n
lower
2
−
1
/
n
upper
2
)
1/\lambda = R_H (1/n_\text{lower}^2 - 1/n_\text{upper}^2)
1/
λ
=
R
H
(
1/
n
lower
2
−
1/
n
upper
2
)
with
R
H
=
1.09678
×
10
7
m
−
1
R_H = 1.09678 \times 10^7\ \text{m}^{-1}
R
H
=
1.09678
×
1
0
7
m
−
1
and
n
lower
=
2
n_\text{lower} = 2
n
lower
=
2
. For the H-alpha transition (
n
upper
=
3
n_\text{upper} = 3
n
upper
=
3
), what is the emitted wavelength in nanometers?
656.5 nm
364.6 nm
486.1 nm
121.5 nm
Check answer