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Multiple choice
The principal quantum number
n
n
n
sets the hydrogen energy via
E
n
=
−
13.6
eV
/
n
2
E_n = -13.6\ \text{eV} / n^2
E
n
=
−
13.6
eV
/
n
2
. An electron occupying the
n
=
3
n = 3
n
=
3
state has what energy (in eV)?
-1.360 eV
-4.533 eV
-1.511 eV
-3.400 eV
Check answer