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Multiple choice
An electron is confined in a 1D infinite square well of width
L
=
0.5
L = 0.5
L
=
0.5
nm. The ground-state (zero-point) energy is
E
1
=
π
2
ℏ
2
/
(
2
m
L
2
)
E_1 = \pi^2 \hbar^2 / (2 m L^2)
E
1
=
π
2
ℏ
2
/
(
2
m
L
2
)
. Using
ℏ
=
1.0546
×
10
−
34
\hbar=1.0546\times10^{-34}
ℏ
=
1.0546
×
1
0
−
34
J·s,
m
=
9.1094
×
10
−
31
m=9.1094\times10^{-31}
m
=
9.1094
×
1
0
−
31
kg,
1
1
1
eV
=
1.6022
×
10
−
19
=1.6022\times10^{-19}
=
1.6022
×
1
0
−
19
J, what is
E
1
E_1
E
1
in eV?
🔬 try it before you answer
6.02 eV
0.752 eV
0.376 eV
1.50 eV
Check answer