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Multiple choice
An electron is confined in a 1D infinite square well of width
L
=
1
L = 1
L
=
1
nm, with
E
n
=
n
2
π
2
ℏ
2
/
(
2
m
L
2
)
E_n = n^2 \pi^2 \hbar^2 / (2 m L^2)
E
n
=
n
2
π
2
ℏ
2
/
(
2
m
L
2
)
. Using
ℏ
=
1.05457
×
10
−
34
\hbar=1.05457\times10^{-34}
ℏ
=
1.05457
×
1
0
−
34
J·s,
m
=
9.10938
×
10
−
31
m=9.10938\times10^{-31}
m
=
9.10938
×
1
0
−
31
kg,
1
1
1
eV
=
1.60218
×
10
−
19
=1.60218\times10^{-19}
=
1.60218
×
1
0
−
19
J, what is the
n
=
2
n = 2
n
=
2
energy
E
2
E_2
E
2
in eV?
🔬 try it before you answer
3.384 eV
0.376 eV
1.504 eV
0.752 eV
Check answer