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Multiple choice
Why are position x and momentum p called incompatible observables, with no quantum state being a simultaneous eigenstate of both?
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Measuring x physically disturbs the apparatus used to measure p
Their commutator [x, p] = i*hbar is non-zero
Position is Hermitian but momentum is not, so they cannot be compared
Their commutator [x, p] = 0, so they commute trivially
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