|q⟩
Bad Qubits
Play
Quest
Questions
Learn
Playground
☕
← Question Bank
Multiple choice
An electron (
m
=
9.109
×
10
−
31
m = 9.109\times 10^{-31}
m
=
9.109
×
1
0
−
31
kg) is accelerated through 150 V, so
K
E
=
150
e
KE = 150e
K
E
=
150
e
with
e
=
1.602
×
10
−
19
e = 1.602\times 10^{-19}
e
=
1.602
×
1
0
−
19
C. Its momentum is
p
=
2
m
⋅
K
E
p = \sqrt{2m \cdot KE}
p
=
2
m
⋅
K
E
and de Broglie wavelength
λ
=
h
/
p
\lambda = h/p
λ
=
h
/
p
with
h
=
6.626
×
10
−
34
J⋅s
h = 6.626\times 10^{-34} \text{ J·s}
h
=
6.626
×
1
0
−
34
J⋅s
. What is
λ
\lambda
λ
in meters?
🔬 try it before you answer
1.00e-9 m
1.23e-10 m
1.00e-10 m
5.01e-11 m
Check answer