|q⟩
Bad Qubits
Play
Quest
Questions
Learn
Playground
☕
← Question Bank
Multiple choice
The de Broglie relation assigns a wavelength to a particle of momentum p. What is that wavelength (h is Planck's constant)?
🔬 try it before you answer
lambda = h/p
lambda = h/p^2
lambda = h*p
lambda = p/h
Check answer