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An electron (
m
=
9.109
×
10
−
31
m = 9.109\times 10^{-31}
m
=
9.109
×
1
0
−
31
kg) is accelerated through
V
=
100
V = 100
V
=
100
V, gaining kinetic energy
K
=
e
V
K = eV
K
=
e
V
with
e
=
1.602
×
10
−
19
e = 1.602\times 10^{-19}
e
=
1.602
×
1
0
−
19
C. Its momentum is
p
=
2
m
K
p = \sqrt{2mK}
p
=
2
m
K
and de Broglie wavelength
λ
=
h
/
p
\lambda = h/p
λ
=
h
/
p
with
h
=
6.626
×
10
−
34
J⋅s
h = 6.626\times 10^{-34} \text{ J·s}
h
=
6.626
×
1
0
−
34
J⋅s
. What is
λ
\lambda
λ
in meters?
6.13e-11 m
1.51e-20 m
1.23e-10 m
1.23e-9 m
Check answer