Multiple choice
Run this circuit, then measure. With what probability do you get |01⟩?
const theta = Math.PI / 3; const c = circuit(2); c.x(1); // |01>: one excitation c.cx(1, 0); // controlled-RY(theta), control 0, target 1 c.ry(theta / 2, 1); c.cx(0, 1); c.ry(-theta / 2, 1); c.cx(0, 1); c.cx(1, 0); return c;
Commit your prediction for P(|01⟩) — then run it.