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Multiple choice
Compared to the Jordan–Wigner transform, what is the main advantage of the Bravyi–Kitaev (BK) transform for mapping fermionic operators to qubits?
It uses far fewer qubits than Jordan–Wigner (about log n total)
It produces a Hamiltonian that is no longer a sum of Pauli strings
Each fermionic operator acts on only O(log n) qubits instead of O(n)
It makes occupation lookup local while parity lookup costs O(n)
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