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For a purely s-wave (isotropic) scatterer with wavenumber
k
=
2
k = 2
k
=
2
and phase shift
δ
0
=
0.5
\delta_0 = 0.5
δ
0
=
0.5
rad, the scattering amplitude has
∣
f
∣
2
=
(
1
/
k
2
)
sin
2
(
δ
0
)
|f|^2 = (1/k^2) \sin^2(\delta_0)
∣
f
∣
2
=
(
1/
k
2
)
sin
2
(
δ
0
)
, and the total cross section is
σ
=
4
π
∣
f
∣
2
\sigma = 4 \pi |f|^2
σ
=
4
π
∣
f
∣
2
. What is
σ
\sigma
σ
?
1.506
0.181
0.722
2.888
Check answer