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Grover search over N=16N = 16 items with M=1M = 1 marked item uses rotation angle θ=arcsin(1/16)\theta = \arcsin(\sqrt{1/16}). After the optimal r=round(π/(4θ)1/2)=3r = \mathrm{round}(\pi/(4\theta) - 1/2) = 3 iterations, the success probability is sin2((2r+1)θ)\sin^2((2r+1)\theta). What is this probability?