Multiple choice
Run this circuit, then measure. With what probability do you get |1⟩?
const c = circuit(1);
c.h(0); // |0> -> |+> = (|0> + |1>)/sqrt(2)
c.t(0); // |+> -> (|0> + e^{i pi/4}|1>)/sqrt(2) = |T>
return c;Commit your prediction for P(|1⟩) — then run it.