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Multiple choice
A simple recursion gives a fault-tolerance threshold as the root of
2
p
2
−
3
p
+
1
=
0
2p^2 - 3p + 1 = 0
2
p
2
−
3
p
+
1
=
0
that lies strictly between 0 and 1. Using the quadratic formula, what is that threshold
p
p
p
?
0.667
0.5
0.25
1
Check answer