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Bad Qubits
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A rotated surface code uses
n
=
d
2
n = d^2
n
=
d
2
physical qubits, so the distance is
d
=
n
d = \sqrt{n}
d
=
n
. With
n
=
25
n = 25
n
=
25
physical qubits, the number of arbitrary errors it can correct is
t
=
⌊
(
d
−
1
)
/
2
⌋
t = \lfloor (d - 1)/2 \rfloor
t
=
⌊(
d
−
1
)
/2
⌋
. What is
t
t
t
?
2
5
4
3
Check answer