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Shor's nine-qubit [ [ 9 , 1 , 3 ] ] [[9,1,3]] [[ 9 , 1 , 3 ]] code concatenates the phase-flip and bit-flip repetition codes and has n − k = 8 n - k = 8 n − k = 8 independent stabilizer generators. How are these 8 generators split between Z Z Z -type and X X X -type checks? 🔬 try it before you answer
Four Z Z Z -type and four X X X -type generators, evenly split across all nine qubits Two Z Z Z -type generators checking bit parities between blocks, plus six X X X -type generators checking phase parities within blocks Eight Z Z Z -type generators only; the X X X errors are handled without any stabilizer checks Six Z Z Z -type generators ( Z 1 Z 2 , Z 2 Z 3 , Z 4 Z 5 , Z 5 Z 6 , Z 7 Z 8 , Z 8 Z 9 Z_1Z_2, Z_2Z_3, Z_4Z_5, Z_5Z_6, Z_7Z_8, Z_8Z_9 Z 1 Z 2 , Z 2 Z 3 , Z 4 Z 5 , Z 5 Z 6 , Z 7 Z 8 , Z 8 Z 9 ) checking bit parities within each block of three, plus two X X X -type generators ( X 1 . . X 6 , X 4 . . X 9 X_1..X_6, X_4..X_9 X 1 .. X 6 , X 4 .. X 9 ) checking phase parities between blocks Check answer