|q⟩ Bad Qubits

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Multiple choice
The quantum Hamming bound for a non-degenerate [[n,k,d]][[n,k,d]] code that corrects tt errors requires 2kj=0tC(n,j)3j2n2^k \sum_{j=0}^{t} C(n,j) 3^j \le 2^n, where the 3j3^j counts weight-jj Pauli errors (X,Y,ZX,Y,Z per location). For n=5,k=1,t=1n = 5, k = 1, t = 1, what is the left-hand side 2kj=01C(5,j)3j2^k \sum_{j=0}^{1} C(5,j) 3^j?