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A depolarizing channel
E
(
ρ
)
=
(
1
−
p
)
ρ
+
p
(
I
/
2
)
E(\rho) = (1-p) \rho + p (I/2)
E
(
ρ
)
=
(
1
−
p
)
ρ
+
p
(
I
/2
)
with
p
=
0.36
p = 0.36
p
=
0.36
acts on
ρ
=
∣
0
⟩
⟨
0
∣
\rho = |0\rangle\langle 0|
ρ
=
∣0
⟩
⟨
0∣
. The fidelity with the input is
F
=
⟨
0
∣
E
(
ρ
)
∣
0
⟩
F = \sqrt{\langle 0|E(\rho)|0\rangle}
F
=
⟨
0∣
E
(
ρ
)
∣0
⟩
. What is
F
F
F
?
🔬 try it before you answer
0.906
0.64
0.96
0.82
Check answer