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intermediate · Physics · Angular Momentum Theory

Checkpoint: Angular Momentum Algebra

This checkpoint pulls together the whole module: the algebra, the spectrum, the ladder operators, and their matrix elements. Work through the reasoning before running your answer.

What you have built

Over the last eleven lessons you constructed the complete quantum theory of angular momentum from a single seed — the commutator [L^i,L^j]=iεijkL^k[\hat{L}_i, \hat{L}_j] = i\hbar\,\varepsilon_{ijk}\hat{L}_k:

The challenge problem

Take a spin-32\tfrac{3}{2} system, =32\ell = \tfrac{3}{2}, whose four states are labeled m{32,12,+12,+32}m \in \{-\tfrac32, -\tfrac12, +\tfrac12, +\tfrac32\}. Apply the lowering operator to the state m=+12m = +\tfrac12:

L^32,+12=(+1)m(m1)  32,12.\hat{L}_-\,\big|\tfrac32, +\tfrac12\big\rangle = \hbar\sqrt{\ell(\ell+1) - m(m-1)}\;\big|\tfrac32, -\tfrac12\big\rangle.

Substituting =32\ell = \tfrac32 and m=+12m = +\tfrac12 (with =1\hbar = 1):

(+1)=3252=154,m(m1)=12(12)=14,\ell(\ell+1) = \tfrac32\cdot\tfrac52 = \tfrac{15}{4}, \qquad m(m-1) = \tfrac12\cdot\left(-\tfrac12\right) = -\tfrac14, 154(14)=164=4=2.\sqrt{\tfrac{15}{4} - \left(-\tfrac14\right)} = \sqrt{\tfrac{16}{4}} = \sqrt{4} = 2.

Try it

Compute the lowering coefficient for L^\hat{L}_- acting on 32,+12\big|\tfrac32, +\tfrac12\big\rangle and return it. The answer is 22.

Run your code to see the quantum state.

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