Sharing a Bell Pair
Quantum teleportation requires two parties — conventionally called Alice and Bob — to share a pre-entangled pair of qubits before any quantum information can be transferred. This shared pair is the entanglement resource, and it must be in a specific maximally-entangled state known as a Bell state.
The Bell state
The four Bell states are the most-entangled states of two qubits. The one used as the teleportation resource is
Each term carries amplitude , so measuring both qubits yields 00 or 11
with equal probability — each. Crucially, the
two qubits are correlated: you never see 01 or 10. Neither qubit alone has a definite
state; they form one inseparable two-qubit system.
Building it with two gates
Starting from (both qubits in ), a two-step circuit creates :
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Hadamard on qubit 0. This turns into the equal superposition , so the two-qubit state becomes
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CNOT (controlled-X) with control qubit 0 and target qubit 1. The CNOT flips qubit 1 whenever qubit 0 is . Applying it to the state above maps and , giving
The resulting state cannot be written as a product for any single-qubit states and ; that is the mathematical signature of entanglement.
Try it
Prepare by applying a Hadamard to qubit 0 followed by a CNOT from qubit 0 to qubit 1. The grader checks the full state vector; the amplitudes on and must each equal and the amplitudes on and must be zero.
After running, inspect the Amplitudes panel. You should see exactly two non-zero entries —
at index (bitstring 00) and index (bitstring 11) — each with magnitude .
That is the Bell pair both parties will share in teleportation.
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