|q⟩ Bad Qubits

beginner · Programming · The Bloch Sphere

The Equator: |+⟩, |−⟩, |i⟩, |−i⟩

The Bloch sphere has two special poles: 0|0\rangle at the north and 1|1\rangle at the south. Every other point on the sphere is a superposition, and the equator — the great circle lying halfway between the poles — is where things get interesting. The four states that sit squarely on that equator are +|+\rangle, |-\rangle, i|i\rangle, and i|-i\rangle.

The X-basis states: +|+\rangle and |-\rangle

The Hadamard gate takes 0|0\rangle to the +x+x axis and 1|1\rangle to the x-x axis:

+=H0=12(0+1),=H1=12(01).|+\rangle = H|0\rangle = \frac{1}{\sqrt{2}}\bigl(|0\rangle + |1\rangle\bigr), \qquad |-\rangle = H|1\rangle = \frac{1}{\sqrt{2}}\bigl(|0\rangle - |1\rangle\bigr).

These two states form the X basis (also called the Hadamard basis or ±x\pm x basis). The state +|+\rangle sits on the +x+x side of the equator; |-\rangle sits directly opposite on the x-x side. Because they are orthogonal (+=0\langle +|-\rangle = 0), they can serve as an alternative measurement basis — you measure in the X basis by applying HH before a standard readout.

The Y-basis states: i|i\rangle and i|-i\rangle

The +y+y and y-y points on the equator are reached by adding a complex phase. Applying the S gate (phase gate) after Hadamard multiplies the 1|1\rangle amplitude by ii:

i=SH0=12(0+i1).|i\rangle = S H|0\rangle = \frac{1}{\sqrt{2}}\bigl(|0\rangle + i|1\rangle\bigr).

The y-y counterpart is

i=SH0=12(0i1).|-i\rangle = S^\dagger H|0\rangle = \frac{1}{\sqrt{2}}\bigl(|0\rangle - i|1\rangle\bigr).

These two states form the Y basis. On the Bloch sphere, i|i\rangle sits at the +y+y axis of the equator and i|-i\rangle at the y-y axis. Together with the X-basis states, they tile the equator into four equally-spaced points separated by 90°90°.

Why these four states matter

The four equator states are the eigenstates of the XX and YY Pauli operators:

They appear throughout quantum computing: +|+\rangle is the starting state for interference in the Hadamard transform, and the Y-basis states arise naturally in quantum phase estimation and in characterizing qubit noise.

Try it

Prepare the state i=12(0+i1)|i\rangle = \tfrac{1}{\sqrt{2}}\bigl(|0\rangle + i|1\rangle\bigr), which sits on the +y+y axis of the Bloch sphere equator. The grader checks the full statevector (up to global phase).

Run your code to see the quantum state.

After running your circuit, inspect the amplitudes: qubit 0|0\rangle should have amplitude 0.707\approx 0.707 (real) and qubit 1|1\rangle should have amplitude 0.707i\approx 0.707i (purely imaginary). That is the signature of the +y+y equator point.

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