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beginner · Physics · The Schrödinger Equation (Intro)

The Idea of a Wave Equation

By the late 1920s, experiment had established two uncomfortable facts. First, matter has a wave nature: de Broglie's relation λ=h/p\lambda = h/p connects momentum to wavelength. Second, that wave-like quantity — which we call the wave function ψ\psi — must somehow encode all physically accessible information about a particle. The natural next question is: what equation does ψ\psi obey?

What we need from such an equation

A good wave equation for quantum mechanics should satisfy several requirements that we can read off from what we already know:

  1. It must be linear. Superposition is observed — if ψ1\psi_1 and ψ2\psi_2 are both valid states, then c1ψ1+c2ψ2c_1 \psi_1 + c_2 \psi_2 must also be a valid state. Only linear equations preserve this.

  2. It must reproduce the de Broglie relation. A free particle with definite momentum pp and energy EE should correspond to a plane wave ψ(x,t)=Aei(kxωt),\psi(x,t) = A\,e^{i(kx - \omega t)}, where k=p/k = p/\hbar and ω=E/\omega = E/\hbar.

  3. It must encode the energy–momentum relation. For a non-relativistic particle of mass mm moving in a potential V(x,t)V(x,t), the classical energy relation is E=p22m+V.E = \frac{p^2}{2m} + V. The equation for ψ\psi must be consistent with this.

  4. It should be first-order in time. Knowing ψ\psi at one moment should determine ψ\psi at all future moments — just as Newton's second law (first-order in velocity) determines the full trajectory once position and velocity are specified.

Reading off the operators

The plane-wave form ψ=Aei(kxωt)\psi = A\,e^{i(kx-\omega t)} lets us translate derivatives into physical quantities. Differentiating once with respect to xx brings down ik=ip/ik = ip/\hbar:

ψx=ipψpix.\frac{\partial \psi}{\partial x} = \frac{ip}{\hbar}\,\psi \quad \Longrightarrow \quad p \leftrightarrow -i\hbar\frac{\partial}{\partial x}.

Differentiating twice with respect to xx brings down k2=p2/2-k^2 = -p^2/\hbar^2:

2ψx2=p22ψp222x2.\frac{\partial^2 \psi}{\partial x^2} = -\frac{p^2}{\hbar^2}\,\psi \quad \Longrightarrow \quad p^2 \leftrightarrow -\hbar^2\frac{\partial^2}{\partial x^2}.

Differentiating once with respect to tt brings down iω=iE/-i\omega = -iE/\hbar:

ψt=iEψEit.\frac{\partial \psi}{\partial t} = -\frac{iE}{\hbar}\,\psi \quad \Longrightarrow \quad E \leftrightarrow i\hbar\frac{\partial}{\partial t}.

These correspondences are sometimes called operator substitutions: whenever EE or pp appears in a classical expression, replace it with the matching differential operator acting on ψ\psi.

Assembling the equation

Applying both substitutions to the classical energy relation E=p2/(2m)+VE = p^2/(2m) + V and letting the resulting operators act on ψ\psi:

iψt=22m2ψx2+Vψ.i\hbar\frac{\partial \psi}{\partial t} = -\frac{\hbar^2}{2m}\frac{\partial^2 \psi}{\partial x^2} + V\psi.

This is the time-dependent Schrödinger equation in one dimension. Notice:

The wave function carries probability, not energy

One might ask: is ψ\psi itself a physical wave like a water wave or an electromagnetic field? The answer is no — ψ(x,t)2|\psi(x,t)|^2 is a probability density. If the particle is in state ψ\psi, the probability of finding it between xx and x+dxx + dx at time tt is

P(x,t)dx=ψ(x,t)2dx.P(x,t)\,dx = |\psi(x,t)|^2\,dx.

For this to make sense globally, the wave function must be normalizable:

ψ(x,t)2dx=1.\int_{-\infty}^{\infty} |\psi(x,t)|^2\,dx = 1.

Requiring normalization is not a separate postulate — once ψ\psi satisfies the Schrödinger equation with a square-integrable initial condition and a real potential VV, the norm is conserved for all time. This can be shown by differentiating the integral with respect to tt and substituting the equation.

Looking ahead

The Schrödinger equation in full will be explored in the next lesson. The key takeaway here is how the equation is motivated: linearity, the de Broglie relation, the classical energy–momentum connection, and first-order time evolution together point almost uniquely to its form. Understanding this logic makes the equation feel inevitable rather than mysterious.

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