Checkpoint: Quanta and Photons
Module 5 introduced the chain of experiments and ideas that forced physics to abandon continuous energy in favour of discrete quanta. This checkpoint ties those threads together by asking you to apply several results in one calculation.
The key results
Planck's quantization hypothesis. A harmonic oscillator of frequency exchanges energy with the radiation field only in whole multiples of
where is Planck's constant. This single idea fixed the ultraviolet catastrophe and introduced the quantum of action.
Einstein's photon. Light of frequency consists of photons each carrying energy and momentum . The photoelectric effect confirmed that energy arrives in indivisible lumps: below the threshold frequency (where is the work function) no electrons are emitted regardless of intensity.
Compton scattering. When a photon of wavelength scatters off a nearly-free electron at angle , the wavelength increases by
This is only possible if the photon carries momentum — it behaves as a particle in the collision.
The Bohr model. Niels Bohr proposed in 1913 that electrons in hydrogen orbit the nucleus only on discrete circular orbits that satisfy (integer angular momentum). The total mechanical energy on orbit is
where the numerical value is the Rydberg energy . The ground state () sits at ; the ionization threshold is .
de Broglie's matter waves. Louis de Broglie unified the photon relations by assigning a wavelength to any particle of momentum :
This explains Bohr's quantization rule: a stable orbit is one whose circumference fits exactly de Broglie wavelengths, .
Connecting the ideas
The module's central theme is that both radiation and matter are simultaneously wave-like and particle-like. Each experiment added a facet: Planck showed energy is discrete; Einstein showed light is a particle; Compton showed that particle carries momentum; Bohr showed atomic orbits are quantized; de Broglie unified them by treating matter as waves.
The H-alpha line
The most famous line in the hydrogen spectrum is H-alpha, produced when an electron falls from to . The photon energy is
= 13.6\left(\frac{1}{4} - \frac{1}{9}\right)\,\text{eV} = 13.6 \times \frac{5}{36}\,\text{eV} \approx 1.889\,\text{eV}.$$ This corresponds to a wavelength $\lambda = hc/E_\gamma \approx 656\,\text{nm}$, the red line visible in hydrogen discharge tubes and in stellar spectra. ## Try it This is a numerical exercise — your code should `return` a number, not a circuit. Using the Bohr energy formula $E_n = -13.6/n^2\,\text{eV}$, compute the energy of the photon emitted when a hydrogen electron drops from $n = 3$ to $n = 2$. <RunnableExample />Sign in on the full site to ask questions and join the discussion.